乘法公式的运用:①x²+y²=(x+y)-查字典问答网
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  乘法公式的运用:①x²+y²=(x+y)²-_____=(x-y)²+______.②(x-y+z)(-x+y+z)=[z+(______)][z-(______)]=z²-(_____)²

  乘法公式的运用:①x²+y²=(x+y)²-_____=(x-y)²+______.

  ②(x-y+z)(-x+y+z)=[z+(______)][z-(______)]=z²-(_____)²

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2020-06-1514:20
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胡浩

  ①x²+y²=(x+y)²-2xy=(x-y)²+2xy

  ②(x-y+z)(-x+y+z)=[z+(x-y)][z-(x-y)]=z²-(x-y)²

2020-06-15 14:23:14
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