【1/x(x+1)(x+2)+1/(x+1)(x+2)(x+-查字典问答网
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来自方高林的问题

  【1/x(x+1)(x+2)+1/(x+1)(x+2)(x+3).+1/(x+98)(x+99)(x+100)=?】

  1/x(x+1)(x+2)+1/(x+1)(x+2)(x+3).+1/(x+98)(x+99)(x+100)=?

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2020-05-3121:51
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李明章

  1/x(x+1)(x+2)+1/(x+1)(x+2)(x+3).+1/(x+98)(x+99)(x+100)=(1/2){[1/x(x+1)-1/(x+1)(x+2)]+[1/(x+1)(x+2)-1/(x+2)(x+3)]+.+[1/(x+98)(x+99)-1/(x+99)(x+100)]}=(1/2){1/x(x+1)-1/(x+99)(x+100)}=[(x+99)(x...

2020-05-31 21:52:25
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