【1.计算5a/(6a^2c)-7b/(12ac^2)+11-查字典问答网

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　　【1.计算5a/(6a^2c)-7b/(12ac^2)+11c/8a^2b2.计算[y/(x^2-xy)+x(y^2-xy)]/(xy)3.计算{(b-c)/[(a-b)(a-c)]}+{(a-c)/[(b-a)(b-c)]}+{(a-b)/[(c-a)(c-b)]}4.已知3x/(x^2-1)=A/(x+1)+B/(x-1),求A、B的值.】

　　1.计算5a/(6a^2c)-7b/(12ac^2)+11c/8a^2b

　　2.计算[y/(x^2-xy)+x(y^2-xy)]/(xy)

　　3.计算{(b-c)/[(a-b)(a-c)]}+{(a-c)/[(b-a)(b-c)]}+{(a-b)/[(c-a)(c-b)]}

　　4.已知3x/(x^2-1)=A/(x+1)+B/(x-1),求A、B的值.

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2020-06-0100:56

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洪荣晶

　　(1)5a/(6a^2c)-7b/(12ac^2)+11c/8a^2b=(20abc-14a^2b+33c^3)/(24a^2bc^2)(2)[y/(x^2-xy)+x(y^2-xy)]/(xy)=((y^2-x^2)/(xy(x-y))/(xy)=-(x+y)/(x^2y^2)(3){(b-c)/[(a-b)(a-c)]}+{(a-c)/[(b-a)(b-c)]}+{(a-b)/...