来自李凤霞的问题
y=intanx/2求导数和dy
y=intanx/2求导数和dy
1回答
2020-05-2207:57
y=intanx/2求导数和dy
y=intanx/2求导数和dy
y‘=1/tanx/2*tan'x/2=1/tanx/2*sec^2x/2*(x/2)'=1/tanx/2*1/2)=sec^2(x/2)/(2tan(x/2)=sec^2(x/2)/(2tan(x/2))=[1/cos^2(x/2)]*{cos(x/2)/[2sin(x/2)]}=1/[2cos(x/2)sin(x/2)]=1/sinx=cscx