来自陈伟强的问题
解方程:(x^2+3x+1)/(4x^2+16x-1)-(12x^2+18x-3)/(x^2+3x+1)=2
解方程:(x^2+3x+1)/(4x^2+16x-1)-(12x^2+18x-3)/(x^2+3x+1)=2
1回答
2020-05-1609:38
解方程:(x^2+3x+1)/(4x^2+16x-1)-(12x^2+18x-3)/(x^2+3x+1)=2
解方程:(x^2+3x+1)/(4x^2+16x-1)-(12x^2+18x-3)/(x^2+3x+1)=2
题目有点问题,应是(x²+3x+1)/(4x²+6x-1)-(12x²+18x-3)/(x²+3x+1)=2
(x²+3x+1)/(4x²+6x-1)-3(4x²+6x-1)/(x²+3x+1)=2
令(x²+3x+1)/(4x²+6x-1)=m
m-3/m=2
m²-2m-3=0
m=3或-1
(x²+3x+1)/(4x²+6x-1)=3,化简得:11x²+15x-4=0,解得x=(-15±√401)/22
(x²+3x+1)/(4x²+6x-1)=-1,化简得:5x²+9x=0,解得x=0或-9/5
经检验,x=(-15±√401)/22,0,-9/5是原方程的解.