解方程:1/(x的平方+x)+1/(x的平方+3x+2)+1-查字典问答网
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来自卜飞宇的问题

  解方程:1/(x的平方+x)+1/(x的平方+3x+2)+1/(x的平方+5x+6)+1/(x的平方+7x+12)+1/(x的平方+9x+20)=5/(x的平方+11x-708)

  解方程:1/(x的平方+x)+1/(x的平方+3x+2)+1/(x的平方+5x+6)+1/(x的平方+7x+12)+1/(x的平方+9x+20)=5/(x的平方+11x-708)

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2020-05-1501:43
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柯亨玉

  1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)=5/(x的平方+11x-708)1/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)+1/(x+4)-1/(x+5)=5/(x^2+11x-708)1/x-1/(...

2020-05-15 01:44:26
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