两题因式分解:35a^4b^3/21a^2b^4dx^2-(-查字典问答网
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  两题因式分解:35a^4b^3/21a^2b^4dx^2-(y-z)^2/(x+y)^2-z^2解方程:x+2/5x-3=x+2/6+3x

  两题因式分解:35a^4b^3/21a^2b^4dx^2-(y-z)^2/(x+y)^2-z^2解方程:x+2/5x-3=x+2/6+3x

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2020-05-1422:18
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冯明琴

  35a^4b^3/21a^2b^4d

  =35/21d*a^(4-2)b^(3-4)

  =5a²/(3bd)

  x^2-(y-z)^2/(x+y)^2-z^2

  =(x+y-z)(x-y+z)/[(x+y+z)(x+y-z)]

  =(x-y+z)/(x+y+z)

  解方程:

  (x+2)/(5x-3)=(x+2)/(6+3x)

  ∵分母6+3x≠0

  3(x+2)≠0

  ∴x+2≠0

  于是

  5x-3=6+3x

  5x-3x=6+3

  2x=9

  x=9/2

2020-05-14 22:20:53
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