来自蒋磊的问题
【高二均值不等式,已知a,b,c都为正数,求证:(a+b+c)(1/(a+b)+1/(b+c)+1/(a+c))>=9/2已知a,b,c都为正数,求证:(a+b+c)(1/(a+b)+1/(b+c)+1/(a+c))>=9/2用均值不等式,谢谢了】
高二均值不等式,已知a,b,c都为正数,求证:(a+b+c)(1/(a+b)+1/(b+c)+1/(a+c))>=9/2
已知a,b,c都为正数,求证:(a+b+c)(1/(a+b)+1/(b+c)+1/(a+c))>=9/2
用均值不等式,谢谢了
1回答
2020-05-0604:31