来自何开锋的问题
分式方程1x−2−1−x2−x=1的两边同乘以(x-2),约去分母得()A.1+(1-x)=x-2B.1-(1-x)=x-2C.1-(1-x)=1D.1+(1-x)=1
分式方程1x−2−1−x2−x=1的两边同乘以(x-2),约去分母得()
A.1+(1-x)=x-2
B.1-(1-x)=x-2
C.1-(1-x)=1
D.1+(1-x)=1


分式方程1x−2−1−x2−x=1的两边同乘以(x-2),约去分母得()A.1+(1-x)=x-2B.1-(1-x)=x-2C.1-(1-x)=1D.1+(1-x)=1
分式方程1x−2−1−x2−x=1的两边同乘以(x-2),约去分母得()
A.1+(1-x)=x-2
B.1-(1-x)=x-2
C.1-(1-x)=1
D.1+(1-x)=1
观察可得两个分母2-x=-(x-2),所以最简公分母为(x-2),去分母得1+(1-x)=x-2.故选A.