(急!)解三元一次的题,①x+y+z=1x+3y+7z=2x-查字典问答网
分类选择

来自蔡国洋的问题

  (急!)解三元一次的题,①x+y+z=1x+3y+7z=2x+5y+19z=4②x+2y+3z=1x=y+12x+3y+5z=2③x+y+z=1x-y-z-3=0x+2y+3z=-4④3x+4z=235x+y=86x+y+8z=49

  (急!)解三元一次的题,

  ①x+y+z=1x+3y+7z=2x+5y+19z=4

  ②x+2y+3z=1x=y+12x+3y+5z=2

  ③x+y+z=1x-y-z-3=0x+2y+3z=-4

  ④3x+4z=235x+y=86x+y+8z=49

1回答
2020-05-0216:08
我要回答
提示:回答问题需要登录哦!
倪德明

  ①x+y+z=1x+3y+7z=2x+5y+19z=4x+3y+7z-(x+y+z)=2-1得2y+6z=1x+5y+19z-(x+3y+7z)=4-2得2y+12z=2可知z=1/6,y=0,代入x+y+z=1,得x=5/6②x+2y+3z=1x=y+12x+3y+5z=2将x=y+1代入x+2y+3z=1得y=-z将x=y+1代入2x+3y+5z=2...

2020-05-02 16:09:06
大家都在问
最新问答