来自付主木的问题
1.(x+6)(x+2)=x(x-3)-21,则x=2.计算:①(π-3)^0+(-0.125)^2009×8^2009②(-3)^2009×(-3分之1)^20083.找规律:(m-1)(m+1)=m^2-1(m-1)(m^2+m+1)=m^3-1(m-1)(m^3+m^2+m+1)+m^4-1(m-1)(m^4+m^3+m^2+m+1)+m^5-1(m-1)(m^5+m^4+m^3+m^2+m+1)=_____-
1.(x+6)(x+2)=x(x-3)-21,则x=
2.计算:①(π-3)^0+(-0.125)^2009×8^2009
②(-3)^2009×(-3分之1)^2008
3.找规律:(m-1)(m+1)=m^2-1
(m-1)(m^2+m+1)=m^3-1
(m-1)(m^3+m^2+m+1)+m^4-1
(m-1)(m^4+m^3+m^2+m+1)+m^5-1
(m-1)(m^5+m^4+m^3+m^2+m+1)=_____-1
……
()(m^n-1+m^n-2+…m^2+m+1)=_______-1
①找出规律
②计算:2+2^2+2^3+…+2^98+2^99
1回答
2020-04-1000:36