来自胡宝芳的问题
【若1a−1b=5,则分式2a+3ab−2ba−2ab−b的值为()A.135B.−35C.35D.1】
若1a−1b=5,则分式2a+3ab−2ba−2ab−b的值为()
A.135
B.−35
C.35
D.1


【若1a−1b=5,则分式2a+3ab−2ba−2ab−b的值为()A.135B.−35C.35D.1】
若1a−1b=5,则分式2a+3ab−2ba−2ab−b的值为()
A.135
B.−35
C.35
D.1
∵1a−1b=5