1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(-查字典问答网

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　　1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+……+1/(x+99)(x+100)

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2020-03-1518:38

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　　1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+……+1/(x+99)(x+100)=[1/x-1/(x+1)]+[1/(x+1)-1/(x+2)]+[1/(x+2)-1/(x+3)]+……+[1/(x+99)-1/(x+100)]=1/x-1/(x+100)=100/x(x+100)

2020-03-15 18:40:47

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