来自万雅竞的问题
limx趋于无穷大[(2^x+3^x)/(2^(x+1)+3^(x+1))],
limx趋于无穷大[(2^x+3^x)/(2^(x+1)+3^(x+1))],
1回答
2020-03-0421:11
limx趋于无穷大[(2^x+3^x)/(2^(x+1)+3^(x+1))],
limx趋于无穷大[(2^x+3^x)/(2^(x+1)+3^(x+1))],
x趋于无穷大lim[(2^x+3^x)/(2^(x+1)+3^(x+1))]
分子分母同时除以3^(x+1)
极限=lim[(1/3)*(2/3)^x+(1/3)]/[(2/3)^(x+1)+1]
=(0+1/3)/(0+1)
=1/3