来自林清的问题
两道math题1.(20-x)(32-x)=5402.(92-2x)(60-x)=885×6
两道math题
1.(20-x)(32-x)=540
2.(92-2x)(60-x)=885×6
1回答
2020-03-0421:18
两道math题1.(20-x)(32-x)=5402.(92-2x)(60-x)=885×6
两道math题
1.(20-x)(32-x)=540
2.(92-2x)(60-x)=885×6
1.(20-x)(32-x)=540x²-52x+100=0(x-50)(x-2)=0所以x=50或者x=22.(92-2x)(60-x)=885×6(46-x)(60-x)=885×3x²-106x+105=0(x-105)(x-1)=0所以x=105或者x=1...