来自李霄的问题
如图,已知△ABC中,AB=AC,AD=AE,∠BAE=30°,则∠DEC等于()A.7.5°B.10°C.15°D.18°
如图,已知△ABC中,AB=AC,AD=AE,∠BAE=30°,则∠DEC等于()
A.7.5°
B.10°
C.15°
D.18°


如图,已知△ABC中,AB=AC,AD=AE,∠BAE=30°,则∠DEC等于()A.7.5°B.10°C.15°D.18°
如图,已知△ABC中,AB=AC,AD=AE,∠BAE=30°,则∠DEC等于()
A.7.5°
B.10°
C.15°
D.18°
∵AC=AB,
∴∠B=∠C,
∵∠AEC=∠B+∠BAE=∠B+30°=∠AED+α,
∴∠B=∠C=∠AED+α-30°,
∵AE=AD,
∴∠AED=∠ADE=∠C+α,
即∠AED=∠AED+α-30°+α,
∴2α=30°,
∴α=15°,
∠DEC=α=15°,
故选C.