来自胡林果的问题
已知集合A={0,1,2},B={z|z=x+y,x∈A,y∈A},则B=()A.{0,1,2,3,4}B.{0,1,2}C.{0,2,4}D.{1,2}
已知集合A={0,1,2},B={z|z=x+y,x∈A,y∈A},则B=()
A.{0,1,2,3,4}
B.{0,1,2}
C.{0,2,4}
D.{1,2}


已知集合A={0,1,2},B={z|z=x+y,x∈A,y∈A},则B=()A.{0,1,2,3,4}B.{0,1,2}C.{0,2,4}D.{1,2}
已知集合A={0,1,2},B={z|z=x+y,x∈A,y∈A},则B=()
A.{0,1,2,3,4}
B.{0,1,2}
C.{0,2,4}
D.{1,2}
∵A={0,1,2},B={z|z=x+y,x∈A,y∈A},
①当x=0,y=0;x=1,y=1;x=2,y=2时,x+y=0,2,4,
②当x=0,y=1;x=1,y=2时,x+y=1,3,
③当x=1,y=0;x=2,y=1时,x+y=1,3,
④当x=0,y=2时,x+y=2,
⑤当x=2,y=0时,x+y=2,
综上,集合B中元素有:{0,1,2,3,4}.
故选:A.