【分式加减法的计算题1:m-1/x+n-m/x2:1/m+3-查字典问答网
分类选择

来自陈明敏的问题

  【分式加减法的计算题1:m-1/x+n-m/x2:1/m+3/m-5/m3:a²/a+b+b²+2ab/a+b4:x-2y/2x-y-x+y/2x-y5:m+2n/n-m+n/n-m-2n/n-m6:x²-5/x-2-x/x-2-1+x/2-x7:先化简,再求值.x²+1/x+1-2/x+1.其中x=1/100】

  分式加减法的计算题

  1:m-1/x+n-m/x

  2:1/m+3/m-5/m

  3:a²/a+b+b²+2ab/a+b

  4:x-2y/2x-y-x+y/2x-y

  5:m+2n/n-m+n/n-m-2n/n-m

  6:x²-5/x-2-x/x-2-1+x/2-x

  7:先化简,再求值.

  x²+1/x+1-2/x+1.其中x=1/100

2回答
2020-01-3117:16
我要回答
提示:回答问题需要登录哦!
黄元元

  2a+1-a+3a2-4a-5÷a2-9a2-3a-10.

  解原式=[x+2x(x-2)-x-1(x-2)2]��x4-x(括号内分式的分母中的多项式式分解因式.分式的除法法则)

  =[(x+2)(x-2)x(x-2)2-x(x-1)x(x-2)2]��x4-x(异分母的分式减法的法则)

  =x2-4-x2+xx(x-2)2��x4-x(整式运算)

  =x-4x(x-2)2��x4-x(合并同类项)

  =x-4x(x-2)2��(-xx-4)(分式的符号法则)

  =-1(x-2)2.(分式的乘法法则)

  计算x+yx2-xy+(x2-y2x)2��(1y-x)3.

  解原式=x+yx(x-y)+(x+y)2(x-y)2x2��1(y-x)3

  =x+yx(x-y)-(x+y)2x2(x-y)

  =x2+xy-x2-2xy-y2x2(x-y)

  =-xy-y2x2(x-y)=-xy+y2x2(x-y).

  x-y+4xyx-y)(x+y-4xyx+y)

  答案x2-y2

  [1(a+b)2-1(a-b)2]÷(1a+b-1a-b)

  答案2a(a+b)(a-b);

  xx-y��y2x+y-x4yx4-y4÷x2x2+y2

  答案-xyx+y

  3x-2x2-x-2+(1-1x+1)÷(1+1x-1)

  答案x2(x+1)(x-2);

  (2xx+1+2x-1+4xx2-1)×(2xx+1+2x-1-4xx2-1).

  答案4

  (2m^2-4m)/(2-m)(m-1)-(1+m)/(1-m^2)

  =2m(m-2)/(2-m)(m-1)-(1+m)/(1-m)(1+m)

  =-2m/(m-1)-1/(1-m)

  =(2m-1)/(1-m)

  (-1)-a^2)/(a-1)-a

  =(1-a-a^2-a^2+a)/(a-1)

  =-(2a^2-1)/(a-1)

  (5/x-1)-(3/x+2)+(3/x+3)-(5/x-2)

  原式=[5(x+2)-3(x-1)]/(x-1)(x+2)-[5(x+3)-3(x-2)]/(x-2)(x+3)

  =(2x+13)/(x��+x-2)-(2x+21)/(x��+x-6)

  =[(2x+13)(x��+x-6)-(2x+21)(x��+x-2)]/(x��+x-6)(x��+x-2)

  =(2x��+16x��+x-78-2x��-23x��-17x+42)/(x��+x-6)(x��+x-2)

  =(-7x��-16x-36)/(x^4+2x��-7x��-8x+12)

  1/6x-4y-1/6x+4y+3x/4y^2-9x^2

  =[6x+4y-(6x-4y)-12x]/(36x^2-16y^2)

  =(8y-12x)/(36x^2-16y^2)

  =4(2y-3x)/[4(3x+2y)(3x-2y)]

  =-1/(3x+2y)

  (2)1/1-x+1/1+x+2/1+x^2+4/1+x^4

  =2/(1-x^2)+2/(1+x^2)+4/(1+x^4)

  =4/(1-x^4)+4/(1+x^4)

  =8/(1-x^8)

  1.(2x分之3)+2=0

  2.(x-1分之x)+(x+1分之2)=1

  3.(x+1分之1)-(x��+3x+2分之x��)=-1

  3/2x=-2

  3=-4x

  x=-3/4

  x/(x-1)+2/(x+1)=1

  x(x+1)+2(x-1)=(x-1)(x+1)

  x^2+x+2x-2=x^2-1

  3x=1

  x=1/3

  1/(x+1)-x^2/(x^2+3x+2)=-1

  1/(x+1)-x^2/(x+1)(x+2)=-1

  (x+2)/(x+1)(x+2)-x^2(x+1)(x+2)=-1

  x+2-x^2=-(x+1)(x+2)

  x^2-x-2=x^2+3x+2

  4x=-4

  x=-1

  拓展:原题=1-1/2+1/2-1/3.+1/99-1/100

  =1-1/100

  (2):根据(1)得:

  1-1/2+1/2-1/3+.+1/N-1/(N+1)

  =1-1/(N+1)

  3.(1)1/1*2+1/2*3+1/3*4+...+1/99*100=(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/99-1/100)=1-1/100=99/100

  (2)1/1*2+1/2*3+1/3*4+...+1/n(n+1)==(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+[1/n-1/(n+1)]=1-1/(n+1)=n/(n+1)

2020-01-31 17:19:28
陈明敏

  啥玩意·-·

  这是我的题的答案吗·-·

2020-01-31 17:24:22
大家都在问
最新问答