来自毕伟文的问题
高数中的三角函数sin(π/4+α)=多少sin(π/4-α)=多少cos(π/4+α)=多少cos(π/4-α)=多少tan(π/4+α)=多少tan(π/4-α)=多少
高数中的三角函数
sin(π/4+α)=多少sin(π/4-α)=多少cos(π/4+α)=多少cos(π/4-α)=多少tan(π/4+α)=多少tan(π/4-α)=多少


高数中的三角函数sin(π/4+α)=多少sin(π/4-α)=多少cos(π/4+α)=多少cos(π/4-α)=多少tan(π/4+α)=多少tan(π/4-α)=多少
高数中的三角函数
sin(π/4+α)=多少sin(π/4-α)=多少cos(π/4+α)=多少cos(π/4-α)=多少tan(π/4+α)=多少tan(π/4-α)=多少
sin(π/4+α)=√2/2cosa+√2/2sina
sin(π/4-α)=√2/2cosa-√2/2sina
cos(π/4+α)=√2/2cosa-√2/2sina
cos(π/4-α)=√2/2cosa+√2/2sina
tan(π/4+α)=(1+tana)/(1-tana)
tan(π/4-α)=(1-tana)/(1+tana)