来自傅山的问题
[2sin50°+sin10°(1+根号3tan10°)]根号(2sin^280°)的值
[2sin50°+sin10°(1+根号3tan10°)]根号(2sin^280°)的值
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2020-12-2604:38
[2sin50°+sin10°(1+根号3tan10°)]根号(2sin^280°)的值
[2sin50°+sin10°(1+根号3tan10°)]根号(2sin^280°)的值
原式=[2sin50°+2sin10°*sin(10°+30°)/cos10°]*√2sin80°
=[2cos40°+2sin10°sin40°/cos10°]*√2cos10°
=2√2(cos40°cos10°+sin10°sin40°]
=2√2cos(40°-10°)
=√6