来自郝瑞兵的问题
计算.1-2根号3/1+2根号3+(5+i^19)-(1+i/根号2)^2
计算.1-2根号3/1+2根号3+(5+i^19)-(1+i/根号2)^2
1回答
2020-12-0904:33
计算.1-2根号3/1+2根号3+(5+i^19)-(1+i/根号2)^2
计算.1-2根号3/1+2根号3+(5+i^19)-(1+i/根号2)^2
1-2根号3/1+2根号3+(5+i^19)-(1+i/根号2)^2
=(1-2√3)²/(1-12)+5+i³-(1+2i-1)/2
=(1-4√3+12)/(-11)+5-i-i
=-(13-4√3)/11+5-2i