来自卢绍文的问题
分解因式:xy(xy+1)+(xy+3)−2(x+y+12)−(x+y−1)2.
分解因式:xy(xy+1)+(xy+3)−2(x+y+12)−(x+y−1)2.
1回答
2020-11-1904:50
分解因式:xy(xy+1)+(xy+3)−2(x+y+12)−(x+y−1)2.
分解因式:xy(xy+1)+(xy+3)−2(x+y+12)−(x+y−1)2.
原式=(xy)2+2xy+3-2(x+y)-1-(x+y)2+2(x+y)-1,
=(xy)2+2xy+1-(x+y)2,
=(xy+1)2-(x+y)2,
=(xy+1+x+y)(xy+1-x-y),
=(x+1)(y+1)(x-1)(y-1).