来自李福的问题
若sinθ=(m-3)/(m+5),cosθ=(4-2m)/(m+5),θ∈(π/2,π),则m=,tanθ=
若sinθ=(m-3)/(m+5),cosθ=(4-2m)/(m+5),θ∈(π/2,π),则m=,tanθ=


若sinθ=(m-3)/(m+5),cosθ=(4-2m)/(m+5),θ∈(π/2,π),则m=,tanθ=
若sinθ=(m-3)/(m+5),cosθ=(4-2m)/(m+5),θ∈(π/2,π),则m=,tanθ=
sin²θ+cos²θ=1[(m-3)/(m+5)]²+[(4-2m)/(m+5)]²=1(m-3)²+(4-2m)²=(m+5)²m²-6m+9+16-16m+4m²=m²+10m+254m²-32m-0m=0或m=8(1)m=0,sinθ=-3/5与θ∈(π/2...
sinθ=-3/5与θ∈(π/2,π),为什么矛盾
θ∈(π/2,π),sinθ>0所以矛盾