找出规律,1-5/6+7/12-9/20+11/30-13/-查字典问答网
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  找出规律,1-5/6+7/12-9/20+11/30-13/42=

  找出规律,

  1-5/6+7/12-9/20+11/30-13/42=

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2020-11-0206:19
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邱培林

  1-5/6+7/12-9/20+11/30-13/42+15/56

  =1-(1/2+1/3)+1/3+1/4-(1/4+1/5)+1/5+1/6-(1/6+1/7)+1/7+1/8

  =1-1/2-1/3+1/3+1/4+.+1/7+1/8

  =1-1/2+1/8

  =1/2-1/8

  =3/8

  7.6乘31又2/5加43.9乘2又2/5

  =(7+3/5)*(3+2/5)+(43+9/10)*(2+2/5)

  =38/5*17/5+439/10*12/5

  =1/25*19*17+1/25*6*439

  =1/25(17*19+439*6)

  =1/25*2957

  =2957/25

  =118+7/25

  =118又7/25

  (9又2/7加7又2/9)除以(5/7加5/9)

  =(9+2/7+7+2/9)/(5/7+5/9)

  =(65/7+65/9)/(5/7+5/9)

  =[65(1/7+1/9)]/[5(1/7+1/9)]

  =65/5

  =13

  (8-11/36)+(9-11/36*13)+(10-11/36*17)+(11-11/36*9)

  =8+9+10+11-11/36-11/36*13-11/36*17-11/36*9

  =38-11/36(1+13+17+9)

  =38-11/36*40

  =38-110/9

  =38-(12+2/9)

  =38-12-2/9

  =26-2/9

  =25+7/9

2020-11-02 06:21:21
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