先化简,再求值:(xy-x)/x^2-2xy+y^2*x^2-查字典问答网
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来自董玉涛的问题

  先化简,再求值:(xy-x)/x^2-2xy+y^2*x^2-y^2/x^2,其中:x=-2,y=1/2

  先化简,再求值:(xy-x)/x^2-2xy+y^2*x^2-y^2/x^2,其中:x=-2,y=1/2

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2020-10-0301:02
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韩清怀

  (xy-x)/(x^2-2xy+y^2)*(x^2-y^2)/x^2

  =x(y-x)/(x-y)^2*(x+y)(x-y)/x^2

  =-(x+y)/x

  =-(-2+1/2)/(-2)

  =-3/4

2020-10-03 01:06:14
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