来自何麟书的问题
(2014•泰州)先化简,再求值:(1-3x+2)÷x−1x2+2x-xx+1,其中x满足x2-x-1=0.
(2014•泰州)先化简,再求值:(1-3x+2)÷x−1x2+2x-xx+1,其中x满足x2-x-1=0.
1回答
2020-10-0210:51
(2014•泰州)先化简,再求值:(1-3x+2)÷x−1x2+2x-xx+1,其中x满足x2-x-1=0.
(2014•泰州)先化简,再求值:(1-3x+2)÷x−1x2+2x-xx+1,其中x满足x2-x-1=0.
原式=x+2−3x+2