来自卢昱的问题
[(1/x-2)-1]/(3-x/x^2-4)
[(1/x-2)-1]/(3-x/x^2-4)
1回答
2020-09-2421:01
[(1/x-2)-1]/(3-x/x^2-4)
[(1/x-2)-1]/(3-x/x^2-4)
[(1/x-2)-1]/(3-x/x^2-4)
=[(1/X-2)-(x-2)/(x-2)]{[(x+2)(x-2)]/(3-x)}
=[(3-x)/(x-2)][(x+2)(x-2)/(3-x)]
=x+2.