来自罗进的问题
1/根号3-1+(1/2)^-1-丨1-tan60丨+(x^2+!)^0化简:x^2+6x+9/2(x+3)-x^2-3x/x
1/根号3-1+(1/2)^-1-丨1-tan60丨+(x^2+!)^0
化简:x^2+6x+9/2(x+3)-x^2-3x/x
1回答
2020-09-0713:16
1/根号3-1+(1/2)^-1-丨1-tan60丨+(x^2+!)^0化简:x^2+6x+9/2(x+3)-x^2-3x/x
1/根号3-1+(1/2)^-1-丨1-tan60丨+(x^2+!)^0
化简:x^2+6x+9/2(x+3)-x^2-3x/x
1、=(√3+1)/2+2-(√3-1)+1
=-√3/2+9/2
2、=(x+3)²/2(x+3)-x(x-3)/x
=x/2+3/2-x+3
=-x/2+9/2