来自刘学东的问题
1-1/2+1/6+1/12+20/1.+1/72+1/901x2x3.x19x20问末尾有几个人零?
1-1/2+1/6+1/12+20/1.+1/72+1/901x2x3.x19x20问末尾有几个人零?
1回答
2020-08-1005:45
1-1/2+1/6+1/12+20/1.+1/72+1/901x2x3.x19x20问末尾有几个人零?
1-1/2+1/6+1/12+20/1.+1/72+1/901x2x3.x19x20问末尾有几个人零?
1-1/2+1/6+1/12+1/20.+1/72+1/90
=1-1/2+1/2-1/3+...+1/9-1/10
=1-1/10
=9/10
1x2x3.x19x20问末尾有20÷5=4,20÷125=0.20
4个零