【请问sin(x+π/2)=?cos(x+π/2)=?tan-查字典问答网
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  【请问sin(x+π/2)=?cos(x+π/2)=?tan(x+π/2)=?cot(x+π/2)=?sec(x+π/2)=?csc(x+π/2)=?还有sin(x+π)=?cos(x+π)=?tan(x+π)=?cot(x+π)=?sec(x+π)=?csc(x+π)=?】

  请问sin(x+π/2)=?cos(x+π/2)=?tan(x+π/2)=?cot(x+π/2)=?sec(x+π/2)=?csc(x+π/2)=?

  还有sin(x+π)=?cos(x+π)=?tan(x+π)=?cot(x+π)=?sec(x+π)=?csc(x+π)=?

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2020-08-0223:32
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胡贞华

  sin(x+π/2)=cosxcos(x+π/2)=-sinxtan(x+π/2)=sin(x+π/2)÷cos(x+π/2)=cosx÷(-sinx)=-cotxcot(x+π/2)=1÷tan(x+π/2)=1÷(-cotx)=-tanxsec(x+π/2)=1÷cos(x+π/2)=1÷(-sinx)=(-1/sinx)csc(x+π/2)=...

2020-08-02 23:34:25
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