来自贺利芳的问题
求导:y=ln(x+根号下(1+x^2))
求导:y=ln(x+根号下(1+x^2))
1回答
2020-08-0222:46
求导:y=ln(x+根号下(1+x^2))
求导:y=ln(x+根号下(1+x^2))
y'=1/(x+√(1+x²))*(x+√(1+x²)'(x+√(1+x²)'=1+1/[2√(1+x²)]*(1+x²)'=1+2x/[2√(1+x²)]=1+x/[√(1+x²)]=[x+√(1+x²)]/√(1+x²)所以y'=1/[x+√(1+x²)]*[x+√(1+...