来自邱维宝的问题
一道二元一次方程,800x+1000y=640001000x+1300y-64000=18000求想x,y的值
一道二元一次方程,
800x+1000y=64000
1000x+1300y-64000=18000
求想x,y的值
1回答
2020-07-1923:55
一道二元一次方程,800x+1000y=640001000x+1300y-64000=18000求想x,y的值
一道二元一次方程,
800x+1000y=64000
1000x+1300y-64000=18000
求想x,y的值
800x+1000y=64000
1000x+1300y-64000=18000
化简得﹛10x+12.5y=800(1)
10x+13y=820(2)
(2)-(1)0.5y=20
y=40
∴x=30